select exists(select * from person) as has_record; select person_id in (1,6,8) as one_of_the_chosen_ones, person_id % 2 = 0 has_even_id, * from person;
You have to do this in SQL Server:
select case when exists(select * from person) then convert(bit, 1) else convert(bit, 0) end as has_record; select case when person_id in (1,6,8) then convert(bit, 1) else convert(bit, 0) end as one_of_the_chosen_ones, case when person_id % 2 = 0 then convert(bit, 1) else convert(bit, 0) end as has_even_id, * from person;
No comments:
Post a Comment