select exists(select * from person) as has_record; select person_id in (1,6,8) as one_of_the_chosen_ones, person_id % 2 = 0 has_even_id, * from person;
You have to do this in SQL Server:
select
case when exists(select * from person) then
convert(bit, 1)
else
convert(bit, 0)
end as has_record;
select
case when person_id in (1,6,8) then
convert(bit, 1)
else
convert(bit, 0)
end as one_of_the_chosen_ones,
case when person_id % 2 = 0 then
convert(bit, 1)
else
convert(bit, 0)
end as has_even_id,
*
from person;
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